statistics and probability

4. [-/2 Points] DETAILS BBUNDERSTAT12 8.2.017.5. 5. [-/2 Points] DETAILS BBUNDERSTAT12 8.2.019.5. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER Let x be a random variable that represents red blood cell count (RBC) in milions of cells per cubic millimeter of whole blood. Then x has a distribution that is approximately normal. For the population of healthy female adults, suppose the mean of the x distribution is about 4.74. Suppose that a female patient has taken six laboratory blood tests over the past several months and that the RBC count data sent called the slab aval Snow avalanches can be a real problem for travelers in the western United States and Canada, A very common type of avalanche is e. These have been studied extensively by David McClung, a professor of civil engineering at the University of to the patient's doctor are as follows British Columbia. Suppose slab avalanches studied in a region of Canada had an average thickness of it = 68 com. The ski patrol at Vail, 4.9 4.2 4.5 4.1 4.4 4.3 Colorado, is studying slab avalanches in its region, A random sample of avalanches in spring gave the following thicknesses (in cm). 16 38 65 54 49 62 LA USE SALT 8 65 64 67 63 74 65 79 1) Use a calculator with sample mean and standard deviation keys to find x and s. (Round your answers to two decimal places ) LA USE SALT () Use a calculator with sample mean and standard deviation keys to find x and s. (Round your answers to two decimal places ) x - em (il) Do the given data indicate that the population mean RBC count for this patient is lower than 4.74? Use cx - 0.05. (a) What is the level of significance? (ii) Assume the slab thickness has an approximately normal distribution. Use a 1% level of significance to test the claim that the mean slab thickness in the Vail region is different from that in the region of Canada. State the null and alternate hypotheses. (a) What is the level of significance? OH p = 4.74: H,: A = 4.74 Hy (4 = 4.74: H, M 2 4.74 State the null and alternate hypotheses. OH Me >4.74, H, M4 - 4.74 OHOf 0.250 0 0. 100 0.250 0.010