Step 3 When t = 100 this equals 17.49825 17.49825 Step 4 When t = 1000 this equals 17.4999825 17.4999825 Step 5 The area under the entire curve is given by 1 35 dx. We have 35 x - 3 dx = lim 35 x - 3 dx = t -+ 00 = lim t -+ 00 As t - co it is clear that - approaches 0. Therefore, as t - co we see that 35 35 21 + 2 approaches20. [-/1 Points] DETAILS SCALCET8 7.8.055. MY NOTES PRACTICE ANOTHER The integral 10 Vx (1 + x ) dx is improper for two reasons: The interval [0, co) is infinite and the integrand has an infinite discontinuity at 0. Evaluate it by expressing it as a sum of improper integrals of Type 2 and Type 1 as follows. 10 10 10 dx = V x ( 1 + * ) dx + V x (1 + x ) dx Need Help? Read It Watch It3. [-/8 Points] DETAILS SCALCET8 7.8.518.XP.MI.SA. MY NOTES PRACTICE ANOTHER This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive any points for the skipped part, and you will not be able to come back to the skipped part. Tutorial Exercise Determine whether the integral is convergent or divergent. If it is convergent, evaluate it. Step 1 The improper integral / e-3t dt must be evaluated as the limit , lim b - -co. e - 3t dt. -1 e -3t dt can be done with the substitution u = for which du = dt. Submit |Skip_(you cannot come back) Need Help? Read It