Step 4 HYPOTHESIS TEST OF THE COMPANY CLAIM:Continuing with the color you selected:You will use as your claim from Mars, the appropriated percentage listed for the factory in which it was produced.Using the statistics, you calculated from your sample proportion and a .05 significance level, complete steps A - E, to test the claim found in the attached document for (__Blue __)M&M's.Use 5% significance level.

1. The statistics that are used are:

x =_______________n = ____29_______= ______0.1379 ________ = _____95%______

2.State the Claim?

A:H0:___________________________

H1:___________________________

The claim is in _____H0 or H1___(choice one).

Is it a LEFTor RIGHT or TWO tail test? (choose one)

B:Test Statistic:Calculate the Test Statistic.Explain how you arrived at your answer.

ANS:

TEST STATISTIC IS _____________________________

C:State the:

p-value __________________________ (Picture)

Color Frequency Relative Frequency Margin of Lower Bound Upper Bound (thatip)) Brown 3 0.1034 0.1108 0.0074 0.2143 Blue 4 0.1379 0,1255 0.0124 0.2634 Green 0.2414 0.1557 0.0856 0.3971 Yellow S 0.1724 0 1375 0.0349 0.3099 Orange 4 0.1379 0.1255 0.0124 0.2634 Red 0.2069 0.1474 0.0595 0.3543 Total 29Project 3 Assi... Search Layout References Mailings Review View Developer Help Find AaBbCcDC AaBbCcD( AaBbC AaBbCc] Repla A 1 Normal 1 No Spac... Heading 1 Heading 2 Selec Paragraph Styles Editin Blue What is the POINT ESTIMATE from the sample of the % of ( Blue _) for ALL possible manufactured M&M's? a. The point estimate of p for the ( Blue _) color in all bags of M and M's is p = Frequency/ total frequency = 4/29 = 0.1379 Critical Z-value at 0.05 level of significance is 1.96. (calculated using Excel function NORM.S.INV [0.05/2)) Margin of Error (MoE) = Z* Vp(1-P) = 1.96 * 0.1379(1 -0.1379)/29 =0.1255 b. I am 95% confident that the estimated percentage of (_Blue _) for ALL produced M & M is between 0.0124_