Question
Stuck on Question 17.14 Using the following formula and its marking it wrong: (16,016 x $0.5975781) $9,570.81 (16,016 x $4.0500000) $64,864.80 $9,570.81+ $64,864.80 = 74435.61
Stuck on Question 17.14
Using the following formula and its marking it wrong:
(16,016 x $0.5975781) $9,570.81
(16,016 x $4.0500000) $64,864.80
$9,570.81+ $64,864.80 = 74435.61
PART 4.3 Process Costing - Weighted Average With Spoilage Physical Flow of Units January Work-in-Process - Beginning 3100 Units Started this Period 22500 Units to Account for 25600 Total transferred out 16,016 units {17.01} Normal spoilage (Roundup to the next unit if needed) 801 units {17.02} Abnormal spoilage 783 units {17.03} Work-in-Process - Ending 8,000 units {17.04} Total Accounted for 25,600 units {17.05} Equivalent Units Material (Round to three places, ##.###.###) 25,600.000 {17.06} Equivalent Units Conversion (Round to three places, ##.###.###) 20,800.000 {17.07} 1798 13500 Total cost of Material (Round to two places, ##.###.##) $15,298.00 {17.08} Total cost of Conversion (Round to two places, ##.###.##) $84,240.00 {17.09} Total cost to account for (Round to two places, ##.###.##) $99,538.00 {17.10} $15,298.00 25,600.000 Cost per equivalent unit of Material (Round to seven places, ###.#######) $0.5975781 {17.11} $84,240.00 20,800.000 Cost per equivalent unit of Conversion (Round to seven places, ###.#######) $4.0500000 {17.12} 8000 $0.5975781 $4,780.6248000 $17,740.6248000 3200 $4.0500000 $12,960.00 Cost of the ending inventory, material and convesion (Round to two places, $###,###.## ) $17,740.62 {17.13}
16,016 units $0.5975781 $9,570.81 $4.0500000 $64,864.80 Cost of the units transferred, material and convesion (Round to two places, $###,###.## ) $74,435.61 {17.14}
783 $0.5975781 $467.90 $3,639.05 783 $4.0500000 $3,171.15 Cost of the abnormal spoilage (Round to two places, $###,###.## ) $3,639.05 {17.15}
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