Subject: Compiler construction (Need Answer ASAP)

Q) Draw symbol table for the following code using separate chaining approach. Assume size of the table is 10. Show how the table evolves at each statement. You can calculate hash value using the hash() function provided underneath:

1. public class CC {
2. int a;
3. public void m(int a) {
4. char c='B';
5. {
6. double d=0.0;
7. }
8. }
9. } //end CC class

public int hash( String k ) {

int value = 0;

for( int i=0; i

value = value + (int)k.charAt( i );

}

return value % 10;

} //end HASH() function

Hint: A-Z ranges 65-90 and a-z ranges 97-122. Hence identifier A will have has value 5, B will have 6, and similarly identifier AB will have 1 and so on.