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such as? One needs to derive this version of the mean value property. + The solution to au 1 1 184 + ar2 = 0.0

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such as? One needs to derive this version of the mean value property.
+ The solution to au 1 1 184 + ar2 = 0.0 0 for which the dise D (20:40), r) = {(x,y) (x - 2)2 + (y - 3) 0 such that the disc in entirely contained in ). (Hint: Use a change of variables that maps D((x0, yo).r) to the unit disc centered at the origin: D(0,1)) 1 2 + The solution to au 1 1 184 + ar2 = 0.0 0 for which the dise D (20:40), r) = {(x,y) (x - 2)2 + (y - 3) 0 such that the disc in entirely contained in ). (Hint: Use a change of variables that maps D((x0, yo).r) to the unit disc centered at the origin: D(0,1)) 1 2

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