sum Dur_stay, detail Dur_stay Percentiles Smallest 1% 3 w w 58 w w 10% If W Obs 25 25% 5 Sum of Wgt. 25 50%
sum Dur_stay, detail Dur_stay Percentiles Smallest 1% 3 w w 58 w w 10% If W Obs 25 25% 5 Sum of Wgt. 25 50% 8 Mean 8. 6 Largest Std. Dev. 5 . 715476 75% 11 11 90% 14 14 Variance 32 . 66667 95% 17 17 Skewness 2. 203535 998 30 30 Kurtosis 8. 959067 by Sex, sort : summarize Dur_stay, detail -> Sex = 1 (Male) Dur_stay Percentiles Smallest 1% 3 W 58 w 10% w w W Obs 11 ID W 25% Sum of Wgt. 11 50% 7 Mean 8. 727273 Largest Std. Dev. 7. 913165 75: 11 9 90% 14 11 Variance 62 . 61818 30 14 Skewness 1 . 916305 99% 30 30 Kurtosis 5. 877836 -> Sex = 2 (Female) Dur stay Percentiles Smallest 4 5% 4 5 10% Obs 14 25% 5 Sum of Wgt. 14 50% 8 . 5 Mean 8 .5 Largest Std. Dev. 3. 480716 75% 11 11 90 : 11 11 Variance 12 . 11538 17 11 Skewness . 8120831 99% 17 17 Kurtosis 3 . 522751Question 6 (2 points) ~/ Saved What's the median of the duration of stay for female patients? Question 7 (2 points) ~/ Saved What's the mean of the duration of stay for male patients? Question 8 (2 points) J Saved What's the interquartile range of the duration of stay for the whole dataset? Question 9 (2 points) J Saved What's the standard deviation of the duration of stay for female patients? Question 11 (2 points) v Saved Which sex has a longer duration of hospital stay based on median? Question 12 (2 points) Which sex has a greater variation for the duration of hospital stay? Question 13 (2 points) Which of the following is the most appropriate way to summarize the duration of hospital stay for this dataset? O N=25; median=8.0; interquartile range=6.0 O Mean=8.6; standard deviation=5.7 Q N=25; median=8.0 O N=25; interquartile range
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