Summary: User requests assistance. Title: User Assistance Re As shown in the figure below, a box of mass m = 58.0 kg (initially at rest) is pushed a distance d = 59.0 m across a rough warehouse floor by an applied force of FA = 234 N directed at an angle of 30.0 below the horizontal. The coefficient of kinetic friction between the floor and the box is 0.100. Determine the following. (For parts (a) through (d), give your answer to the nearest multiple of 10.) FAJ30 rough surface (a) work done by the applied force WA = 9640 X Can you write an expression for the work done by a constant force acting over a distance and at some angle with respect to the displacement vector in terms of the magnitude of the force F, the distance d the force acts, and the angle 0 between the direction of the force and the displacement vector? J (b) work done by the force of gravity We = 0 (c) work done by the normal force WN = 0 (d) work done by the force of friction W = 3410 X Pay careful attention to the angle between the direction of the force of friction and the displacement vector. Do you recall how to determine the force of friction in terms of the normal force and the coefficient of friction? A good diagram showing all the forces and their components will help you determine a correct expression for the normal force needed in order to determine the force of friction. J (e) Calculate the net work on the box by finding the sum of all the works done by each individual force. W Net = 13050 X Knowing the work done on the box by each force acting on the box, we can determine the net work done on the box. J (f) Now find the net work by first finding the net force on the box, then finding the work done by this net force. W Net