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Suppose a 1 2 8 Kbps point - to - point link is set up between the earth and a rover on mars. The distance

Suppose a 128 Kbps point-to-point link is set up between the earth and a rover on mars. The distance from the earth to mars (when they are closest together) is approximately 55 Gm, and data travel over the link at the speed of light-3 x 108 m/s.
a) Calculate the delay x bandwidth product for the link. (K=10^3, M=10^6, B=8 bits)
Ans: Propagation delay on the link is (Blank 1*10^9)/(3*10^8)=1845.
The delay x bandwidth product for the link is Blank 2MB (the answer is in an exact float number in the format of x.xXX)
b)
A camera on the rover takes pictures of its surroundings and sends these to Earth. How quickly after a picture is taken can it reach Mission Control on Earth? Assume that each image is 5 Mbit in size.
Ans: Transmit delay for 5 Mbit of data is 5*10^6/ bandwidth = Blank 3s.(round the answer to an integer)
Thus, the total time required is Blank 4 seconds.

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