Suppose a $250,mL$ flask is filled with $1\mathrm{.}7$mol of $C{l}_2$ and $0\mathrm{.}10$mol of $HCl.$ The following reaction becomes possible:

$H_2(g)+C{l}_2(g)2HCl(g)$

The equilibrium constant $K$ for this reaction is $0\mathrm{.}800$ at the temperature of the flask.

Calculate the equilibrium molarity of $H_2.$ Round your answer to two decimal places.