Suppose a $500.mL$ flask is filled with $0\mathrm{.}50$mol of $H_2$ and $0\mathrm{.}80$mol of $I_2.$ The following reaction becomes possible:

$H_2(g)+I_2(g)2HI(g)$

The equilibrium constant $K$ for this reaction is $9\mathrm{.}52$ at the temperature of the flask.

Calculate the equilibrium molarity of $I_2.$ Round your answer to two decimal places.