Suppose a survey asked 827 randomly sampled registered voters in California "Do you support? Or do you oppose? Drilling for oil and natural gas off the Coast of California? Or do you not know enough to say?" Below is the distribution of responses, separated based on whether or not the respondent graduated from college. College Grad Yes No Support 155 133 Oppose 181 125 Do not know 103 130 Total 439 388 Complete a chi-square test for these data to check whether there is a statistically significant difference in responses from college graduates and non-graduates. (Use a significance level of 0.05.) State the null and alternative hypothesis. O Ho: " support = Moppose = "do not know H : at least two of the group means, A support' "oppose' "do not know are not equal O Hot H support F Hoppose # # do not know H : at least two of the group means, "support' oppose' "do not know are equal Ho: The opinion of college grads and non-grads is different on the topic of drilling for oil and natural gas off the coast of California. HA: The opinion of college grads and non-grads is not different on the topic of drilling for oil and natural gas off the coast of California. O Ho: The opinion of college grads and non-grads is not different on the topic of drilling for oil and natural gas off the coast of California. HA: The opinion of college grads and non-grads is different on the topic of drilling for oil and natural gas off the coast of California. Check the relevant conditions. Both samples are Vy random, unrelated, and the samples represent less than 10% of their populations, so independence [is vy satisfied. The expected counts condition [is vy met since the expected count for each group is [greater than V 5. Calculate the test statistic. (Round your answer to two decimal places.) Determine the p-value. (Round your answer to three decimal places.) p-value = Interpret the p-value in context of the hypothesis test. O Fail to reject Ho . The data provide convincing evidence that there is some difference in the opinions for drilling for oil and natural gas off the Coast of California based on whether or not the respondent graduated from college. Reject Ho. The data provide convincing evidence that there is some difference in the opinions for drilling for oil and natural gas off the Coast of California based on whether or not the respondent graduated from college. Reject Ho. The data do not provide convincing evidence that there is some difference in the opinions for drilling for oil and natural gas off the Coast of California based on whether or not the respondent graduated from college. O Fail to reject Ho. The data do not provide convincing evidence that there is some difference in the opinions for drilling for oil and natural gas off the Coast of California based on whether or not the respondent graduated from college. You may need to use the appropriate technology to answer this question.New TV shows air each fall. Prior to getting a spot on the air, tests are run to gauge public opinion about the show. Here are data on a new show. Is there an association between liking the show and age of viewer? Adults Children Total Like It 40 40 80 Indifferent 20 19 39 Dislike 5 30 35 Total 65 89 154 (a) What is the expected value for the adults who dislike the show? (Round your answer to two decimal places.) 14.49 x expected cell count = [row marginal total)(column marginal total) grand total (b) Calculate the y test statistic. (Round your answer to two decimal places.) 14.17 X x2 = 5 (observed count - expected count) expected count (c) Find the P-value. Based on a significance level of 5%, the correct conclusion is which of the following? (Use a table or technology.) There is sufficient evidence to reject H and conclude that there is an association between liking the show and age of viewer, There is insufficient evidence to reject A and conclude that there is no association between liking the show and age of viewer. There is sufficient evidence to reject H and conclude that there is no association between liking the show and age of viewer. There is insufficient evidence to reject H and conclude that there is an association between liking the show and age of viewer.A pro golfer or dubhea In mah and dis In yards for 20 games. Clubhead Clubhead Distance speed (mph) Speed (mph) (yards) 79 211 95 255 214 96 248 221 97 263 225 273 225 939 283 90 228 100 280 90 233 TOT 286 240 104 289 93 250 106 294 247 106 295 LOL USE SALT (2) The golfer would like to find the least squares regression line pred from clubhead speed (x) for the 20 games she played. Create a scatterplot of the data. Distance 20 40 120 Clubhead Speed Distance Distance Distance 120 120 46 60 120 Clubhead speed Clubhead Speed clubhead speed Does a linear regression model make sense for these data? Ye O NO (b) Calculate the slope. (Round your answer to four decimal places.) Calculate the y-intercept. (Round your answer to four decimal places.) (C) For every 1-mph Increase In swing speed, the distance traveled by the golf ball Increases by 3.7135 yards. True O FaloncThe owner of an outdoor concert arena knows that the greater the amount of snow on the ground, the lower the attendance will be at his venue, which seats 7,500 people. He studies this and collects the following data. Inches of Snow Attendance 15 7,500 7 4,014 2 6,533 S 5,125 7,500 10 1,200 LA USE SALT (2) Look at the scatterplot. Is a linear model appropriate for these data? O No (b) Calculate the slope and y-intercept for the regression line. (Round your answers to four decimal places.) Attendance - -546.3 x (Inches of Snow) + 7676 * (C) Use your rounded equation to predict attendance at a concert when there are 8.2 Inches of snow on the ground. (Round your answer to the nearest integer.) 4124 x peopleThe following regression output is for predicting the heart weight (In g) of cats from their body weight (In kg). The coefficients are estimated using a dataset of 144 domestic cats. Estimate Std. Error t value Pr(>It) ( Intercept) -0.350 1.693 -0.506 0.614 body wt 0.251 16. OBE 5 - 1.454 - 64.57% Fadi - 64.32% 13 Heart weight (@ 2.5 3.0 3.5 4.0 Body weight (ke) (a) Write out the linear model. (Let y represent the heart weight in grams and let x represent their body weight in kilograms. ) (b) Interpret the Intercept. [Give your answer in grams.) The expected heart weight of cats with a body weight of 0 kilograms is D * grams. (C) Interpret the slope. (Give your answer in grams. ) For each additional kilogram in a cat's weight, we expect their hearts to be heavier by |4034 * gram, on average. (d) Interpret As. (Give your answer as a percent.) Body weight explains 64 65 * % of the variability In weights of cats' hearts. (e) Calculate the correlation mefficient. [Round your answer to four decimal places.) 0.6466 1x