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Suppose an insurance company randomly surveyed 738 drivers and found that 686 claimed they always buckled up. Construct a 95% confidence interval for the fraction

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Suppose an insurance company randomly surveyed 738 drivers and found that 686 claimed they always buckled up. Construct a 95% confidence interval for the fraction of all drivers who buckle up. Margin of Error: E We are 95% confident that the fraction of drivers who always buckle up is between and Question Help: D Post to forum

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