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Suppose f is a one-to-one, differentiable function and its inverse function f 1 is also differentiable. One can show, using implicit differentiation (do it!), that

Supposefis a one-to-one, differentiable function and its inverse functionf1is also differentiable. One can show, using implicit differentiation (do it!), that

(f1)(x)=1/f(f1(x))

Iff(4)=5andf(4)=2/3, find(f1)(5).

(f1)(5)=

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