Question
Suppose that a system has a logical address space of size 2 25 bytes= 33554432 bytes and a physical address space of 2 19 bytes=
Suppose that a system has a logical address space of size 225 bytes= 33554432 bytes and a physical address space of 219bytes= 524288 bytes. Suppose the systems use paging for mapping logical pages to physical memory frames. Pages and frame are 4096 bytes. Answer the following.
a. What are the sizes of logical and physical addresses in bits?
b. Draw the logical and physical addresses showing the address fields used for the page number (logical) and frame number (physical) and the byte with the page/frame. Be sure to show the bits that each field uses.
c. How many logical pages are there?
d. How many physical frames are there?
(Please explain all subquestions answers in detail.)
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