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Suppose that insurance companies did a survey. They randomly surveyed 420 drivers and found that 330 claimed they always buckle up. We are interested

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Suppose that insurance companies did a survey. They randomly surveyed 420 drivers and found that 330 claimed they always buckle up. We are interested in the population proportion of drivers who claim they always buckle up. NOTE: If you are using a Student's t-distribution, you may assume that the underlying population is normally distributed. (In general, you must first prove that assumption, though.) Part(a) (i) Enter an exact number as an integer, fraction, or decimal. x= (ii) Enter an exact number as an integer, fraction, or decimal. (iii) Round your answer to four decimal places. p' = (rounded to four decimal places) Part (c) Which distribution should you use for this problem? (Round your answer to four decimal places.) P'~ Explain your choice. O The Student's f-distribution should be used because we do not know the standard deviation. The binomial distribution should be used because there are two outcomes, buckle up or do not buckle up. The Student's f-distribution should be used because npq $10, which implies a small sample. O The normal distribution should be used because we are interested in proportions and the sample size is large. Part (d) Construct a 95% confidence interval for the population proportion who claim they always buckle up. (i) State the confidence interval. (Round your answers to four decimal places.) (ii) Sketch the graph. C.L.= (iii) Calculate the error bound. (Round your answer to four decimal places.) 82 P' Part (e) If this survey were done by telephone, list three difficulties the companies might have in obtaining random results. Only people over the age of 24 would be included in the survey. The individuals in the sample may not accurately reflect the population. Children who do not answer the phone will not be included. Individuals may not tell the truth about buckling up. Individuals may choose to participate or not participate in the phone survey.

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