Suppose that insurance companies did a survey. They randomly surveyed 450 drivers and found that 340 claimed they always buckle up. We are interested in the population proportion of drivers who claim they always buckle up. NOTE: If you are using a Student's t-distribution, you may assume that the underlying population is normally distributed. (In general, you must first prove that assumption, though.) Part (a) (i) Enter an exact number as an integer, fraction, or decimal. x = 340 Correct: Your answer is correct. (ii) Enter an exact number as an integer, fraction, or decimal. n = 450 Correct: Your answer is correct. (iii) Round your answer to four decimal places. p' = .7556 Correct: Your answer is correct. (rounded to four decimal places) Part (b) In words, define the random variables X and P'. X is the number of people who claim they buckle up, and P' is the proportion of people in the sample who buckle up. X is the number of people who do not buckle up, and P' is the proportion of people in the sample who do not buckle up. X is the proportion of people in the sample who claim they buckle up, and P' is the number of people who buckle up. X is the proportion of people in the sample who do not buckle up, and P' is the number of people who do not buckle up. Correct: Your answer is correct. Correct! The random variable of interest, X, is the number of people who buckle up, and P' represents the proportion of the sample who buckle up. Part (c) Which distributio