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Suppose the acceleration of an object is given by ax(t) = 10t^2 e^0.1t + 1. Assuming the object starts from rest, find the velocity vx(t)
Suppose the acceleration of an object is given by ax(t) = 10t^2 e^0.1t + 1. Assuming the object starts from rest, find the velocity vx(t) between time t=0 and time t=5.0s using trapezoidal integration and a time step of 1.0s.
For the previous problem, keep cutting the time step in half until the velocity at t=5.0s changes by less than 0.1% from the previous time step size. What step size accomplishes this?
Perform the previous integral with the MATLAB integral function
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