Suppose the following topology.

where Ci is a client, A is a server and B is a local proxy. My numbers are:26,16,0,6 and 26. Lets SUM=sum of these five decimal numbers. Consider a web page is requested from A by any Ci consisting of text content 8*SUM Kbytes, audio content of 5*SUM Mbytes, video content of 1200*SUM Mbytes and 30 images of 7*SUM Mbytes each. Assume bandwidth SUM/2 Mbps in link AB and SUM/3 Mbps in every link BCi. The distance between client Ci and B is SUM/5*100Km and SUM/3*10Km between A and B, while the propagation speed over these links is 2.8*108 meters/sec. Information is divided in packets with Packet size equal to SUM*100 bits and ACK size equal to 128 bits. The processing and queuing delay together is SUM sec for each packet transmitted in both sides at A, B and any Ci. Initial handshaking needed is as usually 2*RTT. The retransmission protocol is ABP stop and wait. Under these assumptions calculate the expected time needed to fully retrieve this web page for one client only, in case any client- server link ABCi is without errors for 1) Non-Persistent HTTP and 2) Persistent HTTP. Repeat the computations when there are 100 such clients Ci generating 10 such web page requests per min, assuming persistent HTTP and 30% successful hits in the web cache B regarding any object requested.