Suppose there is sufficient evidence to reject Ho: H =H2 H3 using a one-way ANOVA. The mean square error from the ANOVA is determined to be 22.1. The sample means are x = 3.2, X2 = 10.6, and x3 = 19.5, with n = n2 =n3 =3. Use Tukey's test to determine which pairwise means are significantly different using a familywise error rate of a = 0.01. Click here to view page 1 of the table of critical values for Tukey's Test for an alpha of 0.05. Click here to view page 2 of the table of critical values for Tukey's Test for an alpha of 0.05. Click here to view page 1 of the table of critical values for Tukey's Test for an alpha of 0.01. Click here to view page 2 of the table of critical values for Tukey's Test for an alpha of 0.01. Calculate the test statistic qo for each pairwise difference. 912 913 = 923 = (Round to three decimal places as needed.)