Question
Suppose we have a single server in a shop and customers arrive in the shop with a Poisson arrival distribution at a mean rate of
Suppose we have a single server in a shop and customers arrive in the shop with a Poisson arrival distribution at a mean rate of lamda=0.5 customers per minute, i.e. on average one customer appears every 1/lamda = 1/0.5 = 2 minutes. This implies that the interarrival times have an exponential distribution with an average interarrival time of 2 minutes. The server has an exponential service time distribution with a mean service rate of 4 customers per minute, i.e. the service rate =4 customers per minute. Considering this situation - which would you prefer: A. one server working twice as fast; or B. two servers each working at the original rate? Use Queueing Theory to solve this problem, not simulation. Why did you choose A or B? Assume both servers are fed from a single queue (as opposed to two separate lines).
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