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Suppose XN(14,1) Between what xx values does 68.23% of the data lie? The range of x values is centered at the mean of the distribution
Suppose XN(14,1) Between what xx values does 68.23% of the data lie?
The range of x values is centered at the mean of the distribution (i.e., 14).
Enter your answers in increasing order, to the nearest integer.
68.23%of the data lie between and
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