Suppose you change the game in the Monty Hall problem, so that there are 10 closed doors (instead of 3), concealing 1 car and 9 goats. As before, you select one door initially. Now the host opens eight of the other doors, revealing a goat behind each one, i.e. there are still two doors closed, including the one you initially selected.

If you switch your choice of doors, what is the probability of getting the car? Explain your thinking.