Suppose you have a directory named public/that has a lot of files in multiple subdirectories. You are looking for a list of all files inside this directory or its subdirectories that contain the string "linux", and you need, for each file, the file's path (relative to the public/ directory) and each file's owner's user name.

Provide a command that produces the list above. The file name and its owner's user name must be delimited by the character ";". You may use a pipe to combine the output of multiple comments. In particular, note the following commands that may be useful, consult the man pages of these commands for further details:

• The grep command can find a string inside one or more files. Options for this command include the ability to search for files recursively, as well as to list only the names of files with matches without the matched content itself.
• The stat command can provide some metadata information about one or more files. In particular, it has options that specify the format of the output, including which fields to provide.

One of the challenges you may face is that the list of files containing the string will be listed in the standard output, while the stat command expects the list of files to be specified in the command arguments. The command xargs can be used in this context to convert items in a standard output to arguments for another command.

Note that, by default, xargs uses any space-like character to split arguments. If you have files with spaces in their names, though, this can cause xargs to interpret the space as a delimiter between arguments. Make sure you properly use valid options in xargs that ensure files with spaces are properly handled by your command.