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t 1 = n = = 0 t 2 = n = = 1 t 3 = t 1 | | t 2 if t

t1= n ==0
t2= n ==1
t3= t1|| t2
if t3 goto L1
result =1
i =2
L2: t4= i <= n
if t4 goto L3
goto L4
L3: result = result * i
i = i +1
goto L2
L4: return result
L1: return
(2) Draw the control-flow graph (CFG) for your three-address code

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