T = 500C T = 400C Find: vel = ? (M/S) Pi = sobar P = 25 bar Vel, = 73 M/S Vel = ? State 1. Go to table A-3 with so bar and T = 500C. At so bar, Tsat = 264 Since Ti Tsat = SHV " go to super hated Vapor table" (A-4) From Table A-4 with so bar and 500C, V, = CS Scanned with CamScanner h = Water vapor enters an insulated nozzle operating at steady state at 500C, 50 bar, with a velocity of 73 m/s, and exits at 400C, 25 bar. Determine the velocity at the exit, in m/s? TABLE A-5 Properties of Compressed Liquid Water T v X 10 v X 10 C m/kg kJ/kg kj/kg kj/kg - K m/kg kl/kg p = 25 bar = 2.5 MPa h kJ/kg p = 50 bar = 5.0 MPa kj/kg - K (T=223.99C) (T=263.99C) 20 1.0006 83.80 86.30 .2961 -9995 83.65 88.65 .2956 40 1.0067 167.25 169-77 -5715 1.0056 166.95 171.97 -5705 80 1.0280 334.29 336.86 1.0737 1.0268 333-72 338.85 1.0720 100 1.0423 418.24 420.85 1.3050 1.0410 417-52 422.72 1.3030 140 1.0784 587.82 590.52 1.7369 1.0768 586.76 592.15 1.7343 180 1.1261 761.16 763.97 2.1375 1.1240 759.63 765-25 2.1341 200 1.1555 849.9 852.8 2.3294 1.1530 848.1 853-9 2.3255 220 1.1898 940.7 943-7 2.5174 1.1866 938.4 944-4 2.5128 Sat. 1.1973 959-1 962.1 2.5546 1.2859 1147.8 1154.2 2.9202 20.0 212.4 1.1767 0.09963 25.0 224.0 1.1973 0.07998 30.0 233-9 1.2165 0.06668 906.44 2600.3 908.79 959-11 2603.1 962.11 1004.8 2604.1 1890.7 2799-5 2.4474 1841.0 2803.1 2.5547 6.2575 25.0 1008.4 1795-7 2804.2 2.6457 6.1869 30.0 6.3409 20.0 35.0 242.6 1.2347 0.05707 1045-4 40.0 250.4 1.2522 0.04978 1082.3 45.0 257-5 1.2692 0.04406 1116.2 2600.1 2603-7 1049.8 2602.3 1087-3 1121.9 50.0 264.0 1.2859 0.03944 1147-8 2597.1 1154.2 60.0 275.6 1.3187 0.03244 1205-4 2589.7 1213.4 1571.0 1753-7 2803.4 2.7253 6.1253 1714.1 2801.4 2.7964 6.0701 1676.4 2798.3 2.8610 6.0199 45.0 1640.1 2794-3 2.9202 5-9734 50.0 2784-3 35.0 40.0 3.0267 5.8892 60.0