$\backslash$table$[[$Year$,1,2,3,4,5],[$Mileage$,3,000,4,000,3,500,3,850,3,700]]$

a$)$ Using a $2-$year moving average, the forecast for year $6=$ miles $($round your response to the nearest whole number$).$

d$)$ Using exponential smoothing with $=0\mathrm{.}20$ and the forecast for year $1$ being $3,000,$ the forecast for year $6=,$ miles $($round your response to the nearest whole number$).$