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Question 1a

1 A 53.0 kg circus performer oscillates up and down at the end of a Long elastic rope at a rate of once every 4.00 s. The elastic rope obeys Hooke's Law. By how much is the rope extended beyond its unloaded length when the performer hangs at rest? Giye your answer in meters. Two different simple harmonic oscillators have the same natural frequency of 9.20 Hz when they are on the surface of the Earth. The first oscillator is a pendulum, the second is a vertical spring and mass. 3a If both systems are moved to the surface of the moon (g = 1.67 m/s ), what is the new frequency of the pendulum in Hz?3!: Calculate the new frequency 01' the vertical spring and mass in Hz. A simple pendulum is 5.60 m long. What is the period of simple harmonic motion for this pendulum if it is hanging in an elevator that is accelerating upward at 4.30 m/s ? Give your answer in seconds.The figure shows a simple pendulum of length L = 89.0 cm and mass m = 1.60 kg. Its bob is observed to have a speed of vo = 3.40 m/s when the cord makes an angle do = 40.0. L m Vo 9a What is the speed (in m/s) of the bob when it is in its lowest position