TASK 2: ANTIDIFFERENTIATION The graph of y 2 13:63 l 5:132 82v 10 is given in Figure 1. 1 (1) Find the following integral I = / (13:83 + 5a:2 8:1: 10)da: 0 2 (2) Find the following integral I = f (133:3 + 5:132 8w 10)dw l (3) Use the solutions to question (1) and question (2) to nd the area bounded by the curve y : 13:83 + 5:132 83: 10 and the w-axis between 3: = 0 and a: = 2. 2 (4) Find the integral I = / (13a:3 + 53:2 8:1: 10)da~. Explain Why this is not the 0 same as the area you found in question (3). 1