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te molar heat of fusion of rubidium metal is 2.19kJ/mol, whereas its heat of vaporization is 75.8k//mol. a. Why is the heat of vaporization so

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te molar heat of fusion of rubidium metal is 2.19kJ/mol, whereas its heat of vaporization is 75.8k//mol. a. Why is the heat of vaporization so much larger than the heat of fusion? Since conversion from a liquid to a gas breaks many more intermolecular forces than conversion from a solid to a liquid, it requires much more energy. Since conversion from a solid to a liquid breaks many more intermolecular forces than conversion from a liquid to a gas, it requires much less energy. Since conversion from a solid to a liquid breaks many more intermolecular forces than conversion from a liquid to a gas, it requires much more encrgy. Since canversion from a llquid to a gas breaks many more intermolecular forces than conversion from a solid to a liculd, it requires much iess anergy. b. What quantity of heat would be needed to meit 1.00g rubidium at its normal melting point? Heat=J What euantity of heat would be needed to vaporize 1.00g rubidium at its normal bolling point? Hest= What quantity of heat would be evolved if 1.00g rubialum vapor condensed at its normal boiling point? Hebt =

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