Ted throws a ball out a window that is 7m high with a velocity of 45 m/s [30 above the horizontal]. What is the time of flight?

What is the horizontal distance travelled?

What is the velocity on impact?

Question projectile motion figure 4 = 45-0/8 R solution ac direction 4- direction 42 = 45 (0830 4= 45 8:0300 9x = 0 ay = -g = -g. 81-m/ 82 of - 2. = R 9 7. = - 7 motion in y disection Unitooon accelerated motion. f - do = 4 t + 6 9 2 2 -7 = 45Xsim 30 x t - ( x9.8/ x 62 - 2 = HS / - Xxg.8/ x / 2 g. sit - 45t - 14 = 0g. 81 t - ust - 14 = 0 solving Quadratic Equation t = 4. 8796 "a ) Time of flight = 4 . 8796 second. Horizontal distance 24-29= 4 Z unitooroon motion R = 45 028 ( 30 ) X 4. 8796 R = 190.1636 m ( b) Horizontal distance = 190- 1636 / metre Motion in y direction y = y t at Vy = 45 sim (30) - 9.81 x4. 8756 y = 92. 5 - 9.8 / X4:8796 y = - 25. 368876 m/s Motion in a direction YC = 42 = 45x CO8( 30 0) Vc = 38. 971 /g