Test the claim that on average, heights (in feet) of oak trees in a forest are less than heights of pine trees. Use = 0.05. It is known that tree heights follow a normal distribution. The table below shows the results of two random samples. Type Oaks 24 64.6 14.5 Pines 20 70.6 11.2 1. The fact that heights are known to be normally distributed is important in this test because: O this is a Z-test O both standard deviations are less than thirty O this is a T-test both sample sizes are less than thirty The hypotheses are: O Ho : p1 = p2; Ha : p1 # P2 O Ho : /1 2 12; Ha : M1 p2 O Ho : p1 2 p2; Ha : P1 /2 2. This is a O left twoO right tailed test and the distribution used is OZ since both o values are known OZ since testing two proportions OT since both o values are not known The Degrees of Freedom (use the simple estimate discussed in the notes, not the messy formula) are O 24 ON/A; this is a Z-test O 19 3. The STS (round to 3 decimals) is: The P-value (round to 4 decimals) is: 4. The decision at a = 0.05 is: O Do not reject Ho since P > a O Do not reject Ho since P