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Textbook RSA uses moduli of form N = pq with p and q of the same bitlength. For efficiency reasons one can also consider three
Textbook RSA uses moduli of form Npq with p and q of the same bitlength. For efficiency reasons one can also consider threeprime RSA for which Npqr with pq and r of the same bitlength since the best factoring algorithms can not yet exploit this form.
Let pqr and let Npqr Let a threeprime RSA public key be Ne with corresponding private key d Use a natural extension of the fast decryption method stated in the lectures and the Chinese Remainder Theorem, for pq and r in order to decrypt the ciphertext c
Note: your calculations should be based on the knowledge of pq and r and use the Chinese Remainder Theorem.
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