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thank you! A regression of length of eruption (y) for Old Faithful on the waiting time between eruptions (x) yields g= 1.874 +0.0753 x .

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A regression of length of eruption (y) for Old Faithful on the waiting time between eruptions (x) yields g= 1.874 +0.0753 x . The output, at right, from R gives the 95% confidence interval for the mean response when x0 = 80 s. a) ( 1) From the output, what is the value of sellfy) .7 b) ( 1) From the output, what is the value of MSE? c) (2) Determine the standard error for predicting a new eruption when x0 = 80 s, that is 39(9) . d) (3) Determine the 95% prediction interval for a new eruption with xo = 80 s. Hint: the degrees of freedom is the same as from the R output. $fit fit Iwr upr 1 4.17622 4.104848 4.247592 $se.fit [1] @.@3625177 $df [1] 270 $residual.scale [1] 0.4965129

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