The acceleration of a particle is given by $a(t)=-10+17t\frac{m}{s^2}.$ Find the position $($in meter$)$ of the particle at $t=11\mathrm{.}7s.$ The particle started its motion with $14\frac{m}{s}$ at position $x=4\mathrm{.}1m.$

Answer with $2$ decimal place without units.

Answer: