The accompanying data contains a random sample of golf scores from two highly competitive sons of a certain statistics author. Each son claims he is the better golfer. Assume the population variances for each son's golf score are equal. Complete parts a through c. Click the icon to view the data table. O A. HO:H1 - H2>0 OB. HO:H1 - H2 so H1:H1 - H2 50 H1: 1 1 - H2 >0 O C. HO:H1 - H2 = 0 OD. HO:H1 - H2# 0 Hy: 19 - H2 # 0 H1:My - H 2 = 0 i Data Table - X Calculate the test statistic, to Son 1 Son 2 to = 1.52 84 93 (Type an integer or decimal rounded to two decimal places as needed.) 75 77 85 79 Determine the critical value, to / 2. 87 94 82 89 70 to/2 = 2.03 74 97 89 (Type an integer or decimal rounded to three decimal places as needed.) 85 82 75 81 Since | | |to/2|. Ho. There enough evidence to conclude that there is a difference in average golf scores between the two sons. 83 84 98 b. Determine the p-value and interpret the results. 94 82 p-value =[ 97 (Type an integer or decimal rounded to three decimal places as needed.) 90 with the conclusion made in part a. 92 This p-value is the alpha level of 0.05. Therefore, we Ho. This conclusion 80 75 c. Construct a 95% confidence interval to estimate the difference in the average golf score between these two sons. 38 23 LCL - X2 = UCL -X2 = Print Done (Type integers or decimals rounded to two decimal places as needed.) ? Click to select your answer(s) MacBook Air DII DD F10 F12 20 888 F8 F9 esc F4 F5