The amounts of nicotine in a certain brand of cigarette are normally distributed with a mean of 0.888 g and a standard deviation of 0.311 g. The company that produces these cigarettes claims that it has now reduced the amount of nicotine. The supporting evidence consists of a sample of 49 cigarettes with a mean nicotine amount of 0.804 g.

Assuming that the given mean and standard deviationhave NOT changed, find the probability of randomly selecting 49 cigarettes with a mean of 0.804 gor less.

P(M< 0.804 g) =

Enter your answer as a number accurate to 4 decimal places.

NOTE:Answers obtained using exactz-scores orz-scores rounded to 3 decimal places are accepted.

Based on the result above, is it valid to claim that the amount of nicotine is lower?(Let's use a 5% cut-off for our definition of unusual.)

• Yes. The probability of this data is unlikely to have occurred by chance alone.
• No. The probability of obtaining this data is high enough to have been a chance occurrence.