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The answer for B is not 0.718 nor 0,2 nor 0.102 nor 0.13 The answer for C is not 0.997 nor 0,2 For a protein
The answer for B is not 0.718 nor 0,2 nor 0.102 nor 0.13
The answer for C is not 0.997 nor 0,2
For a protein with two ligand binding sites the binding polynomial has the general form: Q=[P](1+2k1[L]+k1k2[L]2) where [P] is the unbound protein concentration and [L] is the free ligand concentration. The equilibrium constants are defined as: k1=[P][L][PL] and k2=[PL][L][PL2] Part A Assume k1=k2=k=10 and [L]=0.15. Calculate the fraction of sites bound fB Consider a model where k1=k and k2=k. If k=10 and [L] =0.15 as before, calculate the binding fraction is =0.1 Repeat the calculation in part A only assume [L]=2. Repeat the calculation in part B only assume [L]=2Step by Step Solution
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