The asteroid Ceres has an orbital speed around the Sun of 17.8926 km/s.

We will assume that the distance from the Earth to the asteroid Ceres at time =

zero is 3.00 x 108 km.

We launch a spacecraft to rendezvous with Ceres. The spacecraft has a speed

of 8.13876689 km/s. Since Ceres is in a circular orbit very far away, we can

assume it is moving in a straight line, no curvature, from right to left when we

launch our s/c. We have to launch where it will be when our s/c arrives. We will

ignore the gravity of the sun, we will assume that our s/c goes in a straight line

to Ceres. All of these are bad assumptions. The purpose of this is to make

simple calculations. Do not overthink this problem.

a) How long, in SECONDS, does it take our spacecraft to get to Ceres?

b) How far did Ceres move during that time? (This is how much we would have

to lead Ceres to rendezvous with it)

c) Now let us violate Rule 7 and round our speed down to 8.13 km/s. How long,

in SECONDS, does it take our s/c to get to Ceres?

d) How far did Ceres move during that time?

e) Subtract d) and b), this is how much we will miss Ceres by rounding down the

velocity.

f) How many times farther is that compared to the distance from the earth to the

moon2 times, 8 times?