- The basic differential equation of the elastic curve for a cantilever beam (shown in Figure 4) is given as EVY =-P (L x), (8) where E is the modulus of elasticity and I is the moment of inertia. Given the parameters E = 200,000 MPa, I = 3 x 10-4m4, P = 5 kN, and L= 3 m, (a) Solve for the analytical solution. -L - - --- - - -- - - --- -- -- -- -- Figure 4: A cantilever beam (b) Solve for deflection using a numerical method, and compare against the analytical solution. - The basic differential equation of the elastic curve for a cantilever beam (shown in Figure 4) is given as EVY =-P (L x), (8) where E is the modulus of elasticity and I is the moment of inertia. Given the parameters E = 200,000 MPa, I = 3 x 10-4m4, P = 5 kN, and L= 3 m, (a) Solve for the analytical solution. -L - - --- - - -- - - --- -- -- -- -- Figure 4: A cantilever beam (b) Solve for deflection using a numerical method, and compare against the analytical solution