1. The below output came from the optimal solution of a toy manufacturing company. The printer had problems and wasnt able to appropriately fill out the LINDO output. Without using LINDO/LINO, please fill in the blank answers and explain how you got to your answer. (15 Points)

OUTPUT:

Max 3x1+7x2+4x3 ST 4x1+5x2+1x3= 8 X2 >=5 X3 >12 END ! Machine 1 Time ! Machine 2 Time ! Demand product A ! Demand product B ! Demand product C LP OPTIMUM FOUND AT STEP 4 OBJECTIVE FUNCTION VALUE A 1) VARIABLE X1 X2 X3 VALUE 8.000000 5.000000 13.000000 REDUCED COST 0.000000 0.000000 0.000000 ROW SLACK OR SURPLUS 2) 0.000000 3) 35.000000 0.000000 5) 0.000000 6) 1.000000 NO. ITERATIONS= 4 DUAL PRICES 4.000000 0.000000 -13.000000 -13.000000 B RANGES IN WHICH THE BASIS IS UNCHANGED: OBJ COEFFICIENT RANGES VARIABLE CURRENT ALLOWABLE ALLOWABLE COEF INCREASE DECREASE X1 3.000000 13.000000 INFINITY X2 7.000000 13.000000 INFINITY X3 INFINITY 2.600000 RIGHTHAND SIDE RANGES ROW CURRENT ALLOWABLE ALLOWABLE RHS INCREASE DECREASE 2 70.000000 11.666667 1.000000 3 90.000000 INFINITY 35.000000 8.000000 0.250000 3.500000 5 5.000000 0.200000 2.333333 6 12.000000 1.000000 INFINITY OWN Max 3x1+7x2+4x3 ST 4x1+5x2+1x3= 8 X2 >=5 X3 >12 END ! Machine 1 Time ! Machine 2 Time ! Demand product A ! Demand product B ! Demand product C LP OPTIMUM FOUND AT STEP 4 OBJECTIVE FUNCTION VALUE A 1) VARIABLE X1 X2 X3 VALUE 8.000000 5.000000 13.000000 REDUCED COST 0.000000 0.000000 0.000000 ROW SLACK OR SURPLUS 2) 0.000000 3) 35.000000 0.000000 5) 0.000000 6) 1.000000 NO. ITERATIONS= 4 DUAL PRICES 4.000000 0.000000 -13.000000 -13.000000 B RANGES IN WHICH THE BASIS IS UNCHANGED: OBJ COEFFICIENT RANGES VARIABLE CURRENT ALLOWABLE ALLOWABLE COEF INCREASE DECREASE X1 3.000000 13.000000 INFINITY X2 7.000000 13.000000 INFINITY X3 INFINITY 2.600000 RIGHTHAND SIDE RANGES ROW CURRENT ALLOWABLE ALLOWABLE RHS INCREASE DECREASE 2 70.000000 11.666667 1.000000 3 90.000000 INFINITY 35.000000 8.000000 0.250000 3.500000 5 5.000000 0.200000 2.333333 6 12.000000 1.000000 INFINITY OWN