The boss states that at least 85% of potential customers must express desire for the service and for those interested, the average cost they are willing to pay is at least 47.50. The boss wants you to be 95% sure of your findings

Mean = 45.58

Standard error = 1.863

Std deviation = 10.86

Conducted survey of potential customers of the 50, 34 expressed an interest in purchasing and the mean maximum price is 31.

Calculate Confidence interval for mean and proportion

What is the sample size needed if you want to be at a 95% level of confidence and have a maximum error of 2 in your estimate of the highest price that consumers are willing to pay?

Please include all formulas and exactly how the numbers plug into the formulas