The classical oscillations of a diatomic molecule consisting of two atoms of masses ml and m2 can be simplified by working in a frame of reference in which the cent-re of mass of the molecule is at rest. In this frame of reference. the total energy of the molecule is given by l l mlmg E = E,\" v2+3k12 where ,u = is called the reduced mass. In this frame of m] + m2 reference the system is reduced to the standard Harmonic Oscillator in which one particle of mass M is attached to a spring of spring constant k. In this problem we look at the emission of a photon by the transition between two adjacent levels of a diatomic molecule. Recall that Ep 2 5E\" sciamr h own (.- hmm where EP 2 T with R being the wavelength of the radiation: and East'fdim\" = (n + 3) an where (on = is the natural angular frequency y of the oscillator. Problem: The transition bet-ween adjacent vibrational levels of the NO molecule gives rise to infrared radiation with wavelength :1 = 5.33 Jrum. Find the value of the elastic constant k characterizing the strength of the bond between the nuclei in the NO molecule. (The reduced mass ,s of the NO molecule is 1.24 X 10.126 kg.) Answer: I; = 1.55 X 103' Nf'm