The compound bar shown below is made of aluminum and steel. The axial forces on the bar are P and 2P. The aluminum segment is 36 inches in length and its area is 0.6 inz. The steel segment is 48 inches in length and the area is 0.4 inz. The modulus of elasticity of aluminum is 10 x 106 psi and that for steel is 29 x 106 psi. 36 inches P 48 inches 2P Aluminum A = 0.6 in 2 6 E = 10 x 10 psi Steel A = 0.4 in 2 6 E = 29 x 10 psi a) Draw free body diagram of each segment of the compound bar clearly showing the force in each material in terms of P. Circle your answer for the force in each material. b) If the maximum allowable stresses in aluminum and steel are 20000 psi and 40000 psi respectively and the applied forces on the compound bar are such that the force in steel is 5P and that in aluminum is 3P, calculate a safe value of P. Use the areas and modulus of elasticity given in the original problem. Put a circle around your final answer. c) If the applied forces on the compound bar are such that the force on the steel is 5P and that in the aluminum is 3P and the total elongation of the compound bar is not to exceed 0.2 inch, calculate P based on this restriction only. Use the lengths, areas and modulus of elasticity given in the original problem.