The data in the table represent the amount of pressure (psi) exerted by a stamping machine (x), and the amount of scrap brass shavings (in pounds) that are collected from the machine each hour (y). Also shown below is the output from statistical technology (Tl-83/84 Calculator). A scatterplot of the data conrms that there is a linear association. Report the equation for predicting scrap brass shavings using words such as scrap, notx and y. State the slope and intercept of the prediction equation. Round all calculations to the nearest thousandth. Li n RegTTest y = a + bx a = 2018775528 b = 2134464237 r2 = 0.997 r = 0.998 O scrap = 2.134 - 2.019(pressure); slope = -2.019 and the intercept is 2.134. O scrap = -2.019 + 2.134(pressure); slope = 2.134 and the intercept is -2.019. O scrap = -2.019 + 2.134(pressure); slope = -2.019 and the intercept is 2.134. O scrap = 2.134 - 2.019(pressure); slope = 2.134 and the intercept is -2.019