Question
The diagram below shows a snapshot of the run-time stack on an LC-3 system while the minMax function is running. There is a comment that
The diagram below shows a snapshot of the run-time stack on an LC-3 system while the minMax function is running. There is a comment that identifies the precise location of the snapshot. Answer the following questions about this program.
What is the return address of the minMax function?
When minMax returns, at what address will it store its return value?
What is the current value of variable z in the main function? What does its value tell you about the while loop?
What is the value of variable t, x, min, and max in the minMax function at the current snapshot? What is the value of *min and *max at the current snapshot?
Is there any meaning behind the value held at address R5+3 when the snapshot is taken?
Which activation records are currently on the stack?
What is the meaning of the value at address 0xFFC6?
What will the value of R5 be after main returns?
int minMax(int *x, int "min, int *max) static double average-0; //global static int count-0; lIglobal intt -*x; count++ average (average (count-1) + "x)/count; R5 13 0xFFCE 0x3104 if(t>"max) max t FFCE FFCD FFCC 20 104 3 if (t average; int main) 0xFFD5 0xFFCF int x=0, min=0, max=0; int z-0; if (1 scanf("%d",8x)) { min X; max = x; ) elsef return 0; while(1-scanf"%d", &x)) z+-minMax(&x, &min, &max); printf("%d %dn", min, max); return 0Step by Step Solution
There are 3 Steps involved in it
Step: 1
Get Instant Access to Expert-Tailored Solutions
See step-by-step solutions with expert insights and AI powered tools for academic success
Step: 2
Step: 3
Ace Your Homework with AI
Get the answers you need in no time with our AI-driven, step-by-step assistance
Get Started