Answered step by step
Verified Expert Solution
Link Copied!

Question

1 Approved Answer

/** The DLinkedList class implements a doubly Linked list. */ class DLinkedList { /** The Node class stores a list element and a reference to

image text in transcribed

/**

The DLinkedList class implements a doubly

Linked list.

*/

class DLinkedList

{

/**

The Node class stores a list element

and a reference to the next node.

*/

private class Node

{

String value; // Value of a list element

Node next; // Next node in the list

Node prev; // Previous element in the list

/**

Constructor.

@param val The element to be stored in the node.

@param n The reference to the successor node.

@param p The reference to the predecessor node.

*/

Node(String val, Node n, Node p)

{

value = val;

next = n;

prev = p;

}

/**

Constructor.

@param val The element to be stored in the node.

*/

Node(String val)

{

// Just call the other (sister) constructor

this(val, null, null);

}

}

private Node first; // Head of the list

private Node last; // Last element on the list

/**

Constructor.

*/

public DLinkedList()

{

first = null;

last = null;

}

/**

The isEmpty method checks to see if the list

is empty.

@return true if list is empty, false otherwise.

*/

public boolean isEmpty()

{

return first == null;

}

/**

The size method returns the length of the list.

@return The number of elements in the list.

*/

public int size()

{

int count = 0;

Node p = first;

while (p != null)

{

// There is an element at p

count ++;

p = p.next;

}

return count;

}

/**

The add method adds to the end of the list.

@param e The value to add.

*/

public void add(String e)

{

if (isEmpty())

{

last = new Node(e);

first = last;

}

else

{

// Add to end of existing list

last.next = new Node(e, null, last);

last = last.next;

}

}

/**

This add method adds an element at an index.

@param e The element to add to the list.

@param index The index at which to add.

@exception IndexOutOfBoundsException

When the index is out of bounds.

*/

public void add(int index, String e)

{

if (index size())

{

String message = String.valueOf(index);

throw new IndexOutOfBoundsException(message);

}

// Index is at least 0

if (index == 0)

{

// New element goes at beginning

Node p = first; // Old first

first = new Node(e, p, null);

if (p != null)

p.prev = first;

if (last == null)

last = first;

return;

}

// pred will point to the predecessor

// of the new node.

Node pred = first;

for (int k = 1; k

{

pred = pred.next;

}

// Splice in a node with the new element

// We want to go from pred-- succ to

// pred--middle--succ

Node succ = pred.next;

Node middle = new Node(e, succ, pred);

pred.next = middle;

if (succ == null)

last = middle;

else

succ.prev = middle;

}

/**

The toString method computes the string

representation of the list.

@return The string representation of the

linked list.

*/

public String toString()

{

StringBuilder strBuilder = new StringBuilder();

// Use p to walk down the linked list

Node p = first;

while (p != null)

{

strBuilder.append(p.value + " ");

p = p.next;

}

return strBuilder.toString();

}

/**

The remove method removes the element

at a given position.

@param index The position of the element

to remove.

@return The element removed.

@exception IndexOutOfBoundsException When

index is out of bounds.

*/

public String remove(int index)

{

if (index = size())

{

String message = String.valueOf(index);

throw new IndexOutOfBoundsException(message);

}

// Locate the node targeted for removal

Node target = first;

for (int k = 1; k

target = target.next;

String element = target.value; // Element to return

Node pred = target.prev; // Node before the target

Node succ = target.next; // Node after the target

// Route forward and back pointers around

// the node to be removed

if (pred == null)

first = succ;

else

pred.next = succ;

if (succ == null)

last = pred;

else

succ.prev = pred;

return element;

}

/**

The remove method removes an element from the list.

@param element The element to remove.

@return true if the element was removed, false otherwise.

*/

public boolean remove(String element)

{

if (isEmpty())

return false;

// Locate the node targeted for removal

Node target = first;

while (target != null

&& !element.equals(target.value))

target = target.next;

if (target == null)

return false;

Node pred = target.prev; // Node before the target

Node succ = target.next; // Node after the target

// Route forward and back pointers around

// the node to be removed

if (pred == null)

first = succ;

else

pred.next = succ;

if (succ == null)

last = pred;

else

succ.prev = pred;

return true;

}

public static void main(String [] args)

{

DLinkedList ll = new DLinkedList();

ll.add("Amy");

ll.add("Bob");

ll.add(0, "Al");

ll.add(2, "Beth");

ll.add(4, "Carol");

System.out.println("The elements of the list are:");

System.out.println(ll);

}

}

List java in Chap 20 (copy it into NetBeans and then right-click, refactor, rename with new name DLinkedList xx i.e. your initials) so it includes a new method named getPriorNode that accepts the String value of an element in the doubly linked list and returns the String value of the previous node (or an appropriate message string if there is none). Email your DLinkedList_xx.java file. To test your logic you should add at the bottom of main() System.out.println("Print the value of System.out.println(Il getPriorNode("Beth"); // Should get Amy /Have a great summer! the Node before Beth:")

Step by Step Solution

There are 3 Steps involved in it

Step: 1

blur-text-image

Get Instant Access to Expert-Tailored Solutions

See step-by-step solutions with expert insights and AI powered tools for academic success

Step: 2

blur-text-image_2

Step: 3

blur-text-image_3

Ace Your Homework with AI

Get the answers you need in no time with our AI-driven, step-by-step assistance

Get Started

Recommended Textbook for

Machine Learning And Knowledge Discovery In Databases European Conference Ecml Pkdd 2014 Nancy France September 15 19 2014 Proceedings Part I Lnai 8724

Authors: Toon Calders ,Floriana Esposito ,Eyke Hullermeier ,Rosa Meo

2014th Edition

3662448475, 978-3662448472

More Books

Students also viewed these Databases questions