The energy balance on fluid flow in a pipe is given by

$\frac{P}{}+\frac{u^2}{\mathrm{.}2}+gz+$widehat$(F)=\frac{W_s^{}}{(m^{})}$

where hat$(F)$ is called the friction loss. You've built a cabin in the hills above Hyalite reservoir, and you installed a pump at the reservoir with a $1-$inch internal diameter pipe going from the pump up to the cabin. The desired flow rate when the pump is on is $10ga\frac{l}{m}in.$ The friction loss $($in $ft*l\frac{b_f}{l}{b}_m)$ is $0\mathrm{.}04*L$ where $L$ is the length of the pipe in $ft.$ If the cabin is $200ft$ up a $30$ slope above the reservoir, what size pump $($in hp$)$ is required? Hint: $1lb{b}_f={?}^{\text{d}\text{e}\text{f}}32\mathrm{.}174lb{b}_m*f\frac{t}{s^2}.$