The equation A = 5500e 0.013t of 1.3% compounded continuously. Use this information to solve the following problems. a. Which logarithm equation shows the amount of time it takes for the investment to grow to $11,000? A. t = 1 0.013 B. t = 2 ln (0.013) C. t = 0.013 In () gives the amount of an initial investment of $5500 after t years at an interest rate-In (2)