The equation below describes the volumetric flow rate in a rectangular channel $(Q_{\text{r}\text{e}\text{c}\text{t}})$ according to Strickler. Program the volumetric flow rate equation for a rectangular channel and find the height of water in the channel $(y)$ in meters to the nearest $1mm$ using trial and error $($and a loop$)$ for the case where: $Q_{\text{r}\text{e}\text{c}\text{t}}=12\frac{m^3}{(s)},w=6m,n=0\mathrm{.}015,$ and $s=0\mathrm{.}0001.$ In one sentence, explain your solution, explain any assumptions required. $[$Course Objectives #$1$ and #$4]$

$Q_{\text{r}\text{e}\text{c}\text{t}}=\frac{(w**y{)}^{\frac{5}{3}}**s^{\frac{1}{2}}}{(w+2**y{)}^{\frac{2}{3}}**n}$

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